対話型チャットで決定したように、これがほとんどの答えです:
SELECT A.projectName as PARENT,COUNT(A.PROJECTNAME) AS PARENTPROJECTCOUNT, B.ProjectName as CHILD, COUNT(B.PROJECTNAME) AS CHILDPROJECT from psprojectitem a INNER JOIN psProjectItem B ON a.objecttype = b.objecttype AND a.objectid1 =b.objectid1 AND a.objectvalue1 = b.objectvalue1 AND a.objectid2 = b.objectid2 AND a.objectvalue2 = b.objectvalue2 AND a.objectid3 = b.objectid3 AND a.objectvalue3 = b.objectvalue3 AND a.objectid4 = b.objectid4 AND a.objectvalue4 = b.objectvalue4 WHERE A.projectname in (SELECT ProjectName from psProjectDefn WHERE lastupdoprid <> 'pplsoft') AND a.projectname <> B.projectName and A.PROJECTNAME = 'AAAA_JOB_KJ' ORDER BY B.PROJECTNAME
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