言われていないことがたくさんあります。私はあなたがあなたの毎日の仕事でより明確な要件を受け取ることを願っています...とにかく、ここにあなたの状況のシミュレーションがあります。これは、データのある日（週に1日）が2007年と2008年で同じであるという仮定に基づいています。
SQL> create table lnd_wkly_plan_rx_summary (pd_end_dt,nrx_cnt)
2 as
3 select date '2008-09-07', 100000 from dual union all
4 select date '2008-09-07', 536619.92 from dual union all
5 select date '2008-09-14', 698082.03 from dual union all
6 select date '2008-09-21', 403604.59 from dual union all
7 select date '2008-09-21', 200000 from dual union all
8 select date '2008-09-21', 100000 from dual union all
9 select date '2008-09-28', 702457.36 from dual union all
10 select date '2007-09-07', 400000 from dual union all
11 select date '2007-09-14', 450000 from dual union all
12 select date '2007-09-21', 500000 from dual union all
13 select date '2007-09-28', 550000 from dual union all
14 select date '2007-09-28', 100000 from dual
15 /
Tabel is aangemaakt.
そして、元のクエリを少し変更しました。
SQL> SELECT pd_end_dt
2 , SUM(nrx_cnt) Total_Count
3 FROM lnd_wkly_plan_rx_summary
4 WHERE pd_end_dt >= date '2008-09-01'
5 AND pd_end_dt < date '2008-09-30'
6 GROUP BY pd_end_dt
7 /
PD_END_DT TOTAL_COUNT
------------------- -----------
07-09-2008 00:00:00 636619,92
14-09-2008 00:00:00 698082,03
21-09-2008 00:00:00 703604,59
28-09-2008 00:00:00 702457,36
4 rijen zijn geselecteerd.
SQL> SELECT pd_end_dt
2 , SUM(nrx_cnt) Total_Count
3 FROM lnd_wkly_plan_rx_summary
4 WHERE pd_end_dt >= date '2007-09-01'
5 AND pd_end_dt < date '2007-09-30'
6 GROUP BY pd_end_dt
7 /
PD_END_DT TOTAL_COUNT
------------------- -----------
07-09-2007 00:00:00 400000
14-09-2007 00:00:00 450000
21-09-2007 00:00:00 500000
28-09-2007 00:00:00 650000
4 rijen zijn geselecteerd.
そして、2007年と2008年のデータを比較できるクエリ：
SQL> select to_char(pd_end_dt,'dd-mm') day_and_month
2 , sum(case trunc(pd_end_dt,'yyyy') when date '2007-01-01' then nrx_cnt end) sum2007
3 , sum(case trunc(pd_end_dt,'yyyy') when date '2008-01-01' then nrx_cnt end) sum2008
4 , sum(case trunc(pd_end_dt,'yyyy') when date '2008-01-01' then nrx_cnt end)
5 - sum(case trunc(pd_end_dt,'yyyy') when date '2007-01-01' then nrx_cnt end) difference
6 , ( sum(case trunc(pd_end_dt,'yyyy') when date '2008-01-01' then nrx_cnt end)
7 - sum(case trunc(pd_end_dt,'yyyy') when date '2007-01-01' then nrx_cnt end)
8 ) / sum(case trunc(pd_end_dt,'yyyy') when date '2008-01-01' then nrx_cnt end) * 100 percentage_difference
9 from lnd_wkly_plan_rx_summary
10 where ( ( pd_end_dt >= date '2007-09-01'
11 and pd_end_dt < date '2007-09-30'
12 )
13 or ( pd_end_dt >= date '2008-09-07'
14 and pd_end_dt < date '2008-09-30'
15 )
16 )
17 group by to_char(pd_end_dt,'dd-mm')
18 /
DAY_A SUM2007 SUM2008 DIFFERENCE PERCENTAGE_DIFFERENCE
----- ---------- ---------- ---------- ---------------------
07-09 400000 636619,92 236619,92 37,1681615
14-09 450000 698082,03 248082,03 35,5376617
21-09 500000 703604,59 203604,59 28,9373595
28-09 650000 702457,36 52457,36 7,46769313
4 rijen zijn geselecteerd.
かなり冗長ですが、それ自体が物語っていると思います。上記のクエリほど集計関数を繰り返さないため、次の書き直しが好きかもしれません。
SQL> select day_and_month
2 , sum2007
3 , sum2008
4 , sum2008-sum2007 difference
5 , 100*(sum2008-sum2007)/sum2008 percentage_difference
6 from ( select to_char(pd_end_dt,'dd-mm') day_and_month
7 , sum(case trunc(pd_end_dt,'yyyy') when date '2007-01-01' then nrx_cnt end) sum2007
8 , sum(case trunc(pd_end_dt,'yyyy') when date '2008-01-01' then nrx_cnt end) sum2008
9 from lnd_wkly_plan_rx_summary
10 where ( pd_end_dt >= date '2007-09-01'
11 and pd_end_dt < date '2007-09-30'
12 )
13 or ( pd_end_dt >= date '2008-09-07'
14 and pd_end_dt < date '2008-09-30'
15 )
16 group by to_char(pd_end_dt,'dd-mm')
17 )
18 /
DAY_A SUM2007 SUM2008 DIFFERENCE PERCENTAGE_DIFFERENCE
----- ---------- ---------- ---------- ---------------------
07-09 400000 636619,92 236619,92 37,1681615
14-09 450000 698082,03 248082,03 35,5376617
21-09 500000 703604,59 203604,59 28,9373595
28-09 650000 702457,36 52457,36 7,46769313
4 rijen zijn geselecteerd.
これがお役に立てば幸いです。
よろしく、ロブ。