datepicker、ajax、php、mysqlを使用して2つの日付の間のレポートを生成するにはどうすればよいですか？

I have Created Whole Tutorial for Date Wise Report, so once try it

テーブル構造

CREATE TABLE IF NOT EXISTS `bookings` (
  `id` int(12) NOT NULL AUTO_INCREMENT,
  `date` date NOT NULL,
  `start` varchar(255) NOT NULL,
  `name` varchar(255) NOT NULL,
  `email` varchar(255) NOT NULL,
  `phone` varchar(20) NOT NULL,
  `comments` longtext NOT NULL,
  `approved` varchar(10) NOT NULL,
  PRIMARY KEY (`id`)
) ENGINE=InnoDB  DEFAULT CHARSET=latin1 AUTO_INCREMENT=3 ;

INSERT INTO `bookings` (`id`, `date`, `start`, `name`, `email`, `phone`, `comments`, `approved`) VALUES
(1, '2014-12-17', 'yes', 'Mahendra', '[email protected]', '89XXXXXXXX', 'nothing', 'yes'),
(2, '2014-12-18', 'no', 'Rahul', '[email protected]', '987XXXXXXX', 'very nice article', 'yes');

my_test.php

<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<script type="text/javascript">
$(document).ready(function(){
  $("#generate_report").click(function(){
	  var from_date=jQuery("#fromdate").val();
	  var to_date=jQuery("#todate").val();
	  var data =
	  {		
	  	from_date	 : from_date,
		to_date		 : to_date
	  }
	jQuery.ajax({	
					type: "POST",
					url: "test.php",
					data: data,
					success: function(responce){
						$("#txtHint").after(responce);
				  }	
			 });
  });
});
</script>

From date: <input type="text" id="fromdate" value="2014-12-17">   To date: <input type="text" id="todate" value="2014-12-18">  
<input type="button" name="generate_report" id="generate_report" value="Generate Report" />
<br>
<div id="txtHint"><b>User informations will be listed here.</b></div>

test.php（ajax呼び出しファイル）

<?php
error_reporting(0);
include_once("wp-config.php");
extract($_POST);
$sql1=mysql_query("Select * from bookings where date between '".$from_date."' AND '".$to_date."'");
echo "<table border='1'>
	  <tr>
		<th>id</th>
		<th>date</th>
		<th>start</th>
		<th>name</th>
		<th>email</th>
		<th>phone</th>
		<th>comments</th>
		<th>approved</th>
	 </tr>";
		while($row = mysql_fetch_array($sql1))
		{
		  echo "<tr>";
			  echo "<td>" . $row['id'] . "</td>";
			  echo "<td>" . $row['date'] . "</td>";
			  echo "<td>" . $row['start'] . "</td>";
			  echo "<td>" . $row['name'] . "</td>";
			  echo "<td>" . $row['email'] . "</td>";
			  echo "<td>" . $row['phone'] . "</td>";
			  echo "<td>" . $row['comments'] . "</td>";
			  echo "<td>" . $row['approved'] . "</td>";
		  echo "</tr>";
		}
echo "</table>";
?>

このデモは完全に機能しており、作成したばかりなので、一度確認してください...

正解してこの解決策に投票するよりも、誰でも興味を持ってください。ありがとう