Oracle 10の場合、アプローチを使用します。問題は、内部クエリのパーティション分割です。
WITH tab as (
SELECT 1 as fdate, 'Apple' as fruit, 1 as num from dual union
SELECT 1 as fdate, 'Apple' as fruit, 2 as num from dual union
SELECT 1 as fdate, 'Apple' as fruit, 3 as num from dual union
SELECT 1 as fdate, 'Kiwi' as fruit, 6 as num from dual union
SELECT 1 as fdate, 'Kiwi' as fruit, 10 as num from dual union
SELECT 2 as fdate, 'Apple' as fruit, 4 as num from dual union
SELECT 2 as fdate, 'Apple' as fruit, 5 as num from dual union
SELECT 2 as fdate, 'Apple' as fruit, 6 as num from dual union
SELECT 2 as fdate, 'Kiwi' as fruit, 4 as num from dual union
SELECT 2 as fdate, 'Kiwi' as fruit, 7 as num from dual )
SELECT fdate, fruit,LTRIM(MAX(SYS_CONNECT_BY_PATH(num,','))
KEEP (DENSE_RANK LAST ORDER BY curr),',') AS fruits_agg
FROM (SELECT fdate,
fruit,
num,
ROW_NUMBER() OVER (PARTITION BY fdate, fruit ORDER BY num) AS curr,
ROW_NUMBER() OVER (PARTITION BY fdate, fruit ORDER BY num) -1 AS prev
FROM tab)
GROUP BY fdate,fruit
CONNECT BY prev = PRIOR curr AND fruit = PRIOR fruit AND fdate = PRIOR fdate
START WITH curr = 1;
与える：
FDATE FRUIT FRUITS_AGG
1 "Kiwi" "6,10"
1 "Apple" "1,2,3"
2 "Kiwi" "4,7"
2 "Apple" "4,5,6"
Oracle11ソリューションははるかに簡単です：
WITH tab as (
SELECT 1 as fdate, 'Apple' as fruit, 1 as num from dual union
SELECT 1 as fdate, 'Apple' as fruit, 2 as num from dual union
SELECT 1 as fdate, 'Apple' as fruit, 3 as num from dual union
SELECT 1 as fdate, 'Kiwi' as fruit, 6 as num from dual union
SELECT 1 as fdate, 'Kiwi' as fruit, 10 as num from dual union
SELECT 2 as fdate, 'Apple' as fruit, 4 as num from dual union
SELECT 2 as fdate, 'Apple' as fruit, 5 as num from dual union
SELECT 2 as fdate, 'Apple' as fruit, 6 as num from dual union
SELECT 2 as fdate, 'Kiwi' as fruit, 4 as num from dual union
SELECT 2 as fdate, 'Kiwi' as fruit, 7 as num from dual )
select fdate
, fruit
, listagg(num,'-') within group ( order by num ) fruit_agg
from tab
group by fdate, fruit
返品：
FDATE FRUIT FRUIT_AGG
1 Kiwi 6-10
1 Apple 1-2-3
2 Kiwi 4-7
2 Apple 4-5-6