繰り返されるキーのMysqlgroup_concatと1つのクエリでの複数の列の繰り返しのカウント（クエリ最適化）

2つのクエリをJOINと組み合わせてみませんか？

SQL：

 SELECT
    tbl1.key1, tbl1.key2, tbl1.info1, tbl1.info2, tbl1.serial_count, tbl1.serial_ids,
    tbl2.product_data_count, tbl2.product_data_ids
 FROM 
 (
select * , count(*) as serial_count,GROUP_CONCAT(key1,' ',key2) as serial_ids from 
 (
 SELECT distinct 
 if(b.serial  < 10,a.key1,null) AS `key1`,
 if(b.serial  < 10,a.key2,null) AS `key2`,
 if(b.serial  < 10,a.info1,null) AS `info1`, 
         if(b.serial  < 10,a.info2,null) AS `info2`
 FROM main_info a inner join product1 b on  a.key1 = b.key1 AND a.key2= b.key2
 ) as sub group by info1,info2
 ) tbl1
 LEFT OUTER JOIN 
 (
select * , count(*) as product_data_count,GROUP_CONCAT(key1,' ',key2) as product_data_ids from 
 (
 SELECT distinct 
 if(b.product_data IS NOT NULL,a.key1,null) AS `key1`,
 if(b.product_data IS NOT NULL,a.key2,null) AS `key2`,
 if(b.product_data IS NOT NULL,a.info1,null) AS `info1`, 
         if(b.product_data IS NOT NULL,a.info2,null) AS `info2`
 FROM main_info a inner join product1 b on  a.key1 = b.key1 AND a.key2= b.key2
 ) as sub group by info1,info2
 ) tbl2
 ON tbl1.info1 = tbl2.info1 AND tbl1.info2 = tbl2.info2
 ORDER BY 3,4
 ;

出力：

mysql>  SELECT
    -> tbl1.key1, tbl1.key2, tbl1.info1, tbl1.info2, tbl1.serial_count, tbl1.serial_ids,
    -> tbl2.product_data_count, tbl2.product_data_ids
    ->  FROM
    ->  (
    -> select * , count(*) as serial_count,GROUP_CONCAT(key1,' ',key2) as serial_ids from
    ->  (
    ->  SELECT distinct
    ->  if(b.serial  < 10,a.key1,null) AS `key1`,
    ->  if(b.serial  < 10,a.key2,null) AS `key2`,
    ->  if(b.serial  < 10,a.info1,null) AS `info1`,
    ->          if(b.serial  < 10,a.info2,null) AS `info2`
    ->  FROM main_info a inner join product1 b on  a.key1 = b.key1 AND a.key2= b.key2
    ->  ) as sub group by info1,info2
    ->  ) tbl1
    ->  LEFT OUTER JOIN
    ->  (
    -> select * , count(*) as product_data_count,GROUP_CONCAT(key1,' ',key2) as product_data_ids from
    ->  (
    ->  SELECT distinct
    ->  if(b.product_data IS NOT NULL,a.key1,null) AS `key1`,
    ->  if(b.product_data IS NOT NULL,a.key2,null) AS `key2`,
    ->  if(b.product_data IS NOT NULL,a.info1,null) AS `info1`,
    ->          if(b.product_data IS NOT NULL,a.info2,null) AS `info2`
    ->  FROM main_info a inner join product1 b on  a.key1 = b.key1 AND a.key2= b.key2
    ->  ) as sub group by info1,info2
    ->  ) tbl2
    ->  ON tbl1.info1 = tbl2.info1 AND tbl1.info2 = tbl2.info2
    ->  ORDER BY 3,4
    ->  ;
+------+------+-------+-------+--------------+-------------+--------------------+------------------+
| key1 | key2 | info1 | info2 | serial_count | serial_ids  | product_data_count | product_data_ids |
+------+------+-------+-------+--------------+-------------+--------------------+------------------+
| NULL | NULL |  NULL |  NULL |            1 | NULL        |               NULL | NULL             |
|    1 |    2 |    14 |    92 |            1 | 1 2         |                  1 | 1 2              |
|    1 |    3 |    15 |    82 |            3 | 1 3,1 4,1 5 |                  3 | 1 3,1 4,1 5      |
|    1 |    1 |    15 |    90 |            1 | 1 1         |                  1 | 1 1              |
|    2 |    1 |    17 |    90 |            1 | 2 1         |                  3 | 2 2,2 3,2 1      |
+------+------+-------+-------+--------------+-------------+--------------------+------------------+
5 rows in set (0.01 sec)

mysql>  select version();
+-----------------+
| version()       |
+-----------------+
| 10.1.10-MariaDB |
+-----------------+
1 row in set (0.00 sec)