これがこの質問に対するmysql/javaソリューションです。
テーブルステートメントの作成:
CREATE TABLE `date_table` (
`ID` bigint(20) NOT NULL AUTO_INCREMENT,
`date` date NOT NULL,
PRIMARY KEY (`ID`)
) ENGINE=InnoDB AUTO_INCREMENT=1 DEFAULT CHARSET=latin1;
Javaコード:
public static void main(String[] args) throws ClassNotFoundException, SQLException {
Database db = new Database("root", "root01", "test-db", "10.10.5.11");
db.connect();
int start_year = 2013;
int end_year = 2100;
for (int year = start_year; year < end_year; year++) {
for (int month = 1; month <= 12; month++) {
int days_in_month = 0;
switch (month) {
case 1: { //January
days_in_month = 31;
break;
}
case 2: { //February
if (year % 4 == 0) {
days_in_month = 29;
} else {
days_in_month = 28;
}
break;
}
case 3: { //March
days_in_month = 31;
break;
}
case 4: { //April
days_in_month = 30;
break;
}
case 5: { //May
days_in_month = 31;
break;
}
case 6: { //June
days_in_month = 30;
break;
}
case 7: { //July
days_in_month = 31;
break;
}
case 8: { //August
days_in_month = 31;
break;
}
case 9: { //September
days_in_month = 30;
break;
}
case 10: { //October
days_in_month = 31;
break;
}
case 11: { //November
days_in_month = 30;
break;
}
case 12: { //December
days_in_month = 31;
break;
}
}
for (int day = 1; day <= days_in_month; day++) {
db.executeInsert("INSERT INTO date_table (date) VALUES ('" + year + "-" + month + "-" + day + "');");
}
}
System.out.println("YEAR: " + year + " FINISHED");
}
}
このSQLを使用して日付のリストを取得します:
SELECT * FROM date_table WHERE YEAR(date) = 2014 AND MONTH(date) = 2;
誰かがそれを使用することを願っています:)