Android->PHP->MYSQLから複数のエントリを挿入します

OK、JSON配列を使用してこの作業を行いました。誰かがそれを使用している場合は、次のようになります：

Android、JSON文字列を作成：

//Create JSON string start
String json_string ="{\"upload_fishes\":[";

//Repeat and loop this until all objects are added (and add try+catch)
JSONObject obj_new = new JSONObject();
obj_new.put("fish_id", your_looped_string_1[i]);
obj_new.put("fish_lat", your_looped_string_2[i]);
obj_new.put("fish_lon", your_looped_string_3[i]);
json_string = json_string + obj_new.toString() + ",";

//Close JSON string
json_string = json_string.substring(0, json_string.length()-1);
json_string += "]}";

AndroidはPHPにデータを送信します（try + catchを追加）：

HttpParams httpParams = new BasicHttpParams();
HttpConnectionParams.setConnectionTimeout(httpParams, TIMEOUT_MILLISEC);
HttpConnectionParams.setSoTimeout(httpParams, TIMEOUT_MILLISEC);
HttpClient client = new DefaultHttpClient(httpParams);

String url = "http://yourserver.com/script.php";

HttpPost request = new HttpPost(url);
request.setEntity(new ByteArrayEntity(json_string.getBytes("UTF8")));
request.setHeader("json", json_string);
HttpResponse response = client.execute(request);

Log.d("FISHY", response.getStatusLine().toString());

PHPスクリプト：

<?php

//CONNECT TO THE DATABASE
 $DB_HOST = 'yourhost.com';
 $DB_USER = 'user';
 $DB_PASS = 'password';
 $DB_NAME = "db_name";

 $mysqli = new mysqli($DB_HOST, $DB_USER, $DB_PASS, $DB_NAME);

 if(mysqli_connect_errno())
{
//    echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
else
{
//    echo "Connected to MySQL";
}


   $postdata = file_get_contents("php://input"); 
   $data = json_decode($postdata, true);

   if (is_array($data['upload_fishes'])) {
      foreach ($data['upload_fishes'] as $record) {
        $fid = $record['fish_id'];
        $flat = $record['fish_lat'];
    $flon = $record['fish_lon'];

        mysqli_query($mysqli,"INSERT INTO `fishes`(`fish_type_id`, `fish_lat`, `fish_lon`) VALUES ($fid, $flat, $flon)");
      }
   }


mysqli_close($mysqli);
?>