SQL Server 2008 でマルチパート識別子をバインドできませんでした

あなたが示したコード例には楕円がありましたが、問題を引き起こしているのは楕円の中にあると思います.

あなたが持っている:

SELECT R.[ID], C.[name] AS [company], ...
FROM [requests] AS R, ...
LEFT OUTER JOIN [companies] AS C
ON R.[company_id] = S.ID

それが次のようなものだとしましょう:

SELECT R.[ID], C.[name] AS [company], X.Field
FROM [requests] AS R, [eXample] as X 
LEFT OUTER JOIN [companies] AS C
ON R.[company_id] = S.ID
WHERE X.[request_id] = R.ID

つまり、ANSI 92 以前の内部結合構文と ANSI 92 外部結合構文の混合です。 SQL Server 2005 でテストすると、リクエストのエイリアス R は、例では R と ... を区切るコンマを超えて表示されず、[eXample] は X として表示されます。ただし、以下は機能しました:

SELECT R.[ID], C.[name] AS [company], X.Field
FROM [eXample] as X, [requests] AS R 
-- Requests and companies on the same side of the comma
LEFT OUTER JOIN [companies] AS C
ON R.[company_id] = S.ID
WHERE X.[request_id] = R.ID

または

SELECT R.[ID], C.[name] AS [company], X.Field
FROM [requests] AS R LEFT OUTER JOIN [companies] AS C
    ON R.[company_id] = S.ID, [eXample] as X 
WHERE X.[request_id] = R.ID
-- Yuck, I would hate to find this. Not at all sure from reading
-- the code how it would work.

ANSI 92 結合構文が好きなので、私のお気に入りです:

SELECT R.[ID], C.[name] AS [company], X.Field
FROM [requests] AS R
INNER JOIN [eXample] as X ON X.[request_id] = R.ID
LEFT OUTER JOIN [companies] AS C ON R.[company_id] = S.ID