最新のSQL を使用 、これはウィンドウ関数 を使用して簡単に実行できます。 :
select invoice_number + 1 as gap_start,
next_nr - 1 as gap_end
from (
select invoice_number,
lead(invoice_number) over (order by invoice_number) as next_nr
from invoices
) nr
where invoice_number + 1 <> next_nr;
SQLFiddle: http://sqlfiddle.com/#!15/1e807/1