合計の問題によるMySQLの結合テーブルグループ

DテーブルとEテーブルの両方をフラット化する必要があります。次に、AとBはCの単なるルックアップであると想定しているため、AでGROUPBYを実行する必要はありません。 http://www.sqlfiddle.com/#!2/fccf1/8

AとBがCの情報の要約にどのように関連しているかが（まだ）わからないため、ノイズ（AとB）を削除しました

これを試してください：

SELECT
       C.Article,
       C.Text,

       COALESCE(D.ClicksSum,0) AS ClicksSum,
       COALESCE(D.ImpressionsSum,0) AS ImpressionsSum,

       COALESCE(E.ViewsSum,0) AS ViewsSum,
       COALESCE(E.VisitorsSum,0) AS VisitorsSum
FROM 
       C

       LEFT JOIN 
       (
         SELECT TableC, SUM(Clicks) AS ClicksSum, SUM(Impressions) AS ImpressionsSum
         FROM D
         GROUP BY TableC
       ) D ON C.ID=D.TableC

       LEFT JOIN 
       (
         SELECT TableC, SUM(Views) AS ViewsSum, SUM(Visitors) AS VisitorsSum
         FROM E
         GROUP BY TableC       
       ) E ON C.ID=E.TableC

出力：

|    ARTICLE |        TEXT | CLICKSSUM | IMPRESSIONSSUM | VIEWSSUM | VISITORSSUM |
----------------------------------------------------------------------------------
|       Type | Unicode Art |        23 |              8 |       23 |           8 |
|     Header | Spreadsheet |        15 |             10 |       32 |          21 |
| Auto Align |         Off |         0 |              0 |        0 |           0 |

sqlfiddleの投稿にこれらのスキーマを手動で入力しなかったことに注意してください。sqlfiddleのTextto DDLを使用しています。

http://sqlfiddle.com が大好きです 、そのテキストからDDLへ ASCIIアートツ

（コメントから）より明確な目的を見ると、これは次のようになります： http：/ /www.sqlfiddle.com/#!2/fccf1/13

SELECT
       A.Name, A.Description,

       COALESCE(SUM(D.ClicksSum),0) AS ClicksSum,
       COALESCE(SUM(D.ImpressionsSum),0) AS ImpressionsSum,

       COALESCE(SUM(E.ViewsSum),0) AS ViewsSum,
       COALESCE(SUM(E.VisitorsSum),0) AS VisitorsSum
FROM 
       C

       LEFT JOIN 
       (
         SELECT TableC, SUM(Clicks) AS ClicksSum, SUM(Impressions) AS ImpressionsSum
         FROM D
         GROUP BY TableC
       ) D ON C.ID=D.TableC

       LEFT JOIN 
       (
         SELECT TableC, SUM(Views) AS ViewsSum, SUM(Visitors) AS VisitorsSum
         FROM E
         GROUP BY TableC       
       ) E ON C.ID=E.TableC

       RIGHT JOIN B ON B.ID = C.TableB
       RIGHT JOIN A ON A.ID = B.TableA

GROUP BY A.ID

出力：

|       NAME | DESCRIPTION | CLICKSSUM | IMPRESSIONSSUM | VIEWSSUM | VISITORSSUM |
----------------------------------------------------------------------------------
|       Type | Unicode Art |        38 |             18 |       55 |          29 |
|     Header | Spreadsheet |         0 |              0 |        0 |           0 |
| Auto Align |         Off |         0 |              0 |        0 |           0 |

上記のアプローチでもデカルト積が生成される可能性があります。SubCategory（B）をフラット化してからCategory（A）にグループ化します。 http://www.sqlfiddle.com/#!2/fccf1/19

SELECT 
  A.Name, A.Description,
  COALESCE(SUM(B.ClicksSum),0) AS ClicksSum,
  COALESCE(SUM(B.ImpressionsSum),0) AS ImpressionsSum,
  COALESCE(SUM(B.ViewsSum),0) AS ViewsSum,
  COALESCE(SUM(B.VisitorsSum),0) AS VisitorsSum
FROM A
LEFT JOIN
(

  SELECT 
    B.ID, B.TableA,
    SUM(C.ClicksSum) AS ClicksSum,
    SUM(C.ImpressionsSum) AS ImpressionsSum,
    SUM(C.ViewsSum) AS ViewsSum,
    SUM(C.VisitorsSum) AS VisitorsSum
  FROM B
  LEFT JOIN
  (

    SELECT
      C.TableB,

      D.ClicksSum,
      D.ImpressionsSum,

      E.ViewsSum,
      E.VisitorsSum
    FROM 
    C

    LEFT JOIN 
    (
      SELECT TableC, SUM(Clicks) AS ClicksSum, SUM(Impressions) AS ImpressionsSum
      FROM D
      GROUP BY TableC
    ) D ON C.ID=D.TableC

    LEFT JOIN 
    (
      SELECT TableC, SUM(Views) AS ViewsSum, SUM(Visitors) AS VisitorsSum
      FROM E
      GROUP BY TableC       
    ) E ON C.ID=E.TableC

  ) C ON C.TableB = B.ID
  GROUP BY B.ID

) B ON B.TableA = A.ID
GROUP BY A.ID

出力：

|       NAME | DESCRIPTION | CLICKSSUM | IMPRESSIONSSUM | VIEWSSUM | VISITORSSUM |
----------------------------------------------------------------------------------
|       Type | Unicode Art |        38 |             18 |       55 |          29 |
|     Header | Spreadsheet |         0 |              0 |        0 |           0 |
| Auto Align |         Off |         0 |              0 |        0 |           0 |