私がここでやろうとしていたことはとても面白いです。過労のせいかもしれません。
mysqli fecthがtrueを返しても、この関数から何も返されませんでした。
したがって、if($ stmt-> fetch()){}ステートメントを変更して配列を返します。
if($stmt->fetch()){
$id = $this->xss_clean($id);
$date = $this->xss_clean($date);
$name = $this->xss_clean($name);
$email = $this->xss_clean($email);
$phone = $this->xss_clean($phone);
$full_address = $this->xss_clean($full_address);
$total_amount_paid = $this->xss_clean($total_amount_paid);
$buyers_account_id = $this->xss_clean($buyers_account_id);
$sellers_account_id = $this->xss_clean($sellers_account_id);
$ad_reference = $this->xss_clean($ad_reference);
$transaction_id = $this->xss_clean($transaction_id);
$status_by_buyers = $this->xss_clean($status_by_buyers);
$status_by_sellers = $this->xss_clean($status_by_sellers);
$net_status = $this->xss_clean($net_status);
return array(
$id,
$date,
$name,
$email,
$phone,
$full_address,
$total_amount_paid,
$buyers_account_id,
$sellers_account_id,
$ad_reference,
$transaction_id,
$status_by_buyers,
$status_by_sellers,
$net_status
);
}