MySQLリレーショナル部門

これを試してみてください：

SELECT DISTINCT fb1.name, fb1.surname FROM favoriteBeer fb1
JOIN stock s ON fb1.beerName = s.beerName
GROUP BY fb1.name, fb1.surname, s.restaurant
HAVING COUNT(*) = (
  SELECT COUNT(*) FROM favoriteBeer fb2
  WHERE fb1.name = fb2.name AND fb1.surname = fb2.surname
)

出力：

|        NAME |   SURNAME |
|-------------|-----------|
|      Bucher |      Rolf |
| Mastroyanni |      Pepe |
|       Meier |      Hans |
|       Meier | Hanspeter |
|       Meier | Hansruedi |
|      Müller |  Heinrich |
|      Peters |     Peter |
|       Zarro |   Darween |

フィドルこちら 。