SQL Server の 3 つの列の日付値を比較し、SQL Server で資産情報を取得する

CASE を使用 最近、2 番目、および最も古い日付を決定する式。それらを CTE に入れます WHERE で列名を使用します 句

WITH CTE AS(
    SELECT *,
        RecentDate =
            CASE
                WHEN APPR_DATE_1 >= APPR_DATE_2 AND APPR_DATE_1 >= APPR_DATE_3 THEN APPR_DATE_1
                WHEN APPR_DATE_2 >= APPR_DATE_3 AND APPR_DATE_2 >= APPR_DATE_1 THEN APPR_DATE_2
                WHEN APPR_DATE_3 >= APPR_DATE_2 AND APPR_DATE_3 >= APPR_DATE_1 THEN APPR_DATE_3
            END,
        SecondDate =
            CASE
                WHEN APPR_DATE_1 BETWEEN APPR_DATE_2 AND APPR_DATE_3 OR APPR_DATE_1 BETWEEN APPR_DATE_3 AND APPR_DATE_2 THEN APPR_DATE_1
                WHEN APPR_DATE_2 BETWEEN APPR_DATE_1 AND APPR_DATE_3 OR APPR_DATE_1 BETWEEN APPR_DATE_3 AND APPR_DATE_1 THEN APPR_DATE_2
                WHEN APPR_DATE_3 BETWEEN APPR_DATE_1 AND APPR_DATE_2 OR APPR_DATE_1 BETWEEN APPR_DATE_2 AND APPR_DATE_1 THEN APPR_DATE_3
            END,
        OldestDate =
            CASE
                WHEN APPR_DATE_1 <= APPR_DATE_2 AND APPR_DATE_1 <= APPR_DATE_3 THEN APPR_DATE_1
                WHEN APPR_DATE_2 <= APPR_DATE_3 AND APPR_DATE_2 <= APPR_DATE_1 THEN APPR_DATE_2
                WHEN APPR_DATE_3 <= APPR_DATE_2 AND APPR_DATE_3 <= APPR_DATE_1 THEN APPR_DATE_3             
            END
    FROM #ASSET
)
SELECT
    APPR_DATE_1, APPR_DATE_2, APPR_DATE_3, ID, NAME, ADDRESS 
FROM CTE
WHERE
    DATEDIFF(DAY, SecondDate, RecentDate) > 365
    OR DATEDIFF(DAY, OldestDate, SecondDate) > 365
  

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