このように書き直すことができます
WITH ADMISSION_OUTSIDE AS
( .....
.....
)
SELECT 'OK' WHERE EXISTS (SELECT * FROM ADMISSION_OUTSIDE)
UNION ALL
SELECT 'NOT OK' WHERE NOT EXISTS (SELECT * FROM ADMISSION_OUTSIDE)
これがデモです
;WITH CTE AS
(
SELECT 1 as a WHERE 1=0
)
SELECT 'OK' WHERE EXISTS (SELECT * FROM CTE)
UNION ALL
SELECT 'NOT OK' WHERE NOT EXISTS (SELECT * FROM CTE)
結果: NOT OK
;WITH CTE AS
(
SELECT 1 as a WHERE 1=1
)
SELECT 'OK' WHERE EXISTS (SELECT * FROM CTE)
UNION ALL
SELECT 'NOT OK' WHERE NOT EXISTS (SELECT * FROM CTE)
結果: OK