FROM OPENXML
を使用した古いアプローチ ここでのオプションかもしれません。 この回答を確認してください
。
このリンク John Cappellettiが時々投稿する関数があり、XML(関数のコードの下のクレジット)を細断処理します。
しかし、私にはわかりません、あなたが本当に達成しようとしていること...なぜあなたは道が必要なのですか?すべてのターゲットノードの値に関心がある場合は、次のようにすることができます(//
を使用した詳細検索 正確なXPath
は必要ありません )
SELECT t.value(N'(text())[1]','nvarchar(max)')
FROM @xml.nodes('//target') AS A(t);
本当にすべてが必要な場合 これを確認できます:
CREATE FUNCTION [dbo].[udf-XML-Hier](@XML xml)
Returns Table
As Return
with cte0 as (
Select Lvl = 1
,ID = Cast(1 as int)
,Pt = Cast(NULL as int)
,Element = x.value('local-name(.)','varchar(150)')
,Attribute = cast('' as varchar(150))
,Value = x.value('text()[1]','varchar(max)')
,XPath = cast(concat(x.value('local-name(.)','varchar(max)'),'[' ,cast(Row_Number() Over(Order By (Select 1)) as int),']') as varchar(max))
,Seq = cast(1000000+Row_Number() over(Order By (Select 1)) as varchar(max))
,AttData = x.query('.')
,XMLData = x.query('*')
From @XML.nodes('/*') a(x)
Union All
Select Lvl = p.Lvl + 1
,ID = Cast( (Lvl + 1) * 1024 + (Row_Number() Over(Order By (Select 1)) * 2) as int ) * 10
,Pt = p.ID
,Element = c.value('local-name(.)','varchar(150)')
,Attribute = cast('' as varchar(150))
,Value = cast( c.value('text()[1]','varchar(max)') as varchar(max) )
,XPath = cast(concat(p.XPath,'/',c.value('local-name(.)','varchar(max)'),'[',cast(Row_Number() Over(PARTITION BY c.value('local-name(.)','varchar(max)') Order By (Select 1)) as int),']') as varchar(max) )
,Seq = cast(concat(p.Seq,' ',10000000+Cast( (Lvl + 1) * 1024 + (Row_Number() Over(Order By (Select 1)) * 2) as int ) * 10) as varchar(max))
,AttData = c.query('.')
,XMLData = c.query('*')
From cte0 p
Cross Apply p.XMLData.nodes('*') b(c)
)
, cte1 as (
Select R1 = Row_Number() over (Order By Seq),A.*
From (
Select Lvl,ID,Pt,Element,Attribute,Value,XPath,Seq From cte0
Union All
Select Lvl = p.Lvl+1
,ID = p.ID + Row_Number() over (Order By (Select NULL))
,Pt = p.ID
,Element = p.Element
,Attribute = x.value('local-name(.)','varchar(150)')
,Value = x.value('.','varchar(max)')
,XPath = p.XPath + '/@' + x.value('local-name(.)','varchar(max)')
,Seq = cast(concat(p.Seq,' ',10000000+p.ID + Row_Number() over (Order By (Select NULL)) ) as varchar(max))
From cte0 p
Cross Apply AttData.nodes('/*/@*') a(x)
) A
)
Select A.R1
,R2 = IsNull((Select max(R1) From cte1 Where Seq Like A.Seq+'%'),A.R1)
,A.Lvl
,A.ID
,A.Pt
,A.Element
,A.Attribute
,A.XPath
,Title = Replicate('|---',Lvl-1)+Element+IIF(Attribute='','','@'+Attribute)
,A.Value
From cte1 A
/*
Source: http://beyondrelational.com/modules/2/blogs/28/posts/10495/xquery-lab-58-select-from-xml.aspx
Taken from John Cappelletti: https://stackoverflow.com/a/42729851/5089204
Declare @XML xml='<person><firstname preferred="Annie" nickname="BeBe">Annabelle</firstname><lastname>Smith</lastname></person>'
Select * from [dbo].[udf-XML-Hier](@XML) Order by R1
*/
GO
DECLARE @xml XML=
'<log>
<clients>
<client>
<section name ="Apps">
<questions>
<groupone>
<question>
<target>Age</target>
</question>
<question>
<target> Height</target>
</question>
<question>
<target> Weight</target>
</question>
</groupone>
<grouptwo name = "exercise">
<wording>what is your name</wording>
<question>
<id>1</id>
<target>def</target>
</question>
</grouptwo>
</questions>
</section>
</client>
</clients>
</log>';
SELECT * FROM dbo.[udf-XML-Hier](@xml);
GO